Question

3.Решите уравнения: а) 506 +х= 2003; б) 601 – х = 408;
в) 243 - (y+83) = 112.​

Answer 1

$506 + x = 2003 \\ x = 2003 - 506 \\ x = 1497$

$601 - x = 408 \\ - x = 408 - 601 \\ - x = - 193 \\ x = 193$

$243 - (y + 83) = 112 \\ 243 - y - 83 = 112 \\ 160 - y = 112 \\ - y = 112 - 160 \\ - y = - 48 \\ y = 48$