Предмет: Математика, автор: amongus18

298. ЗАПОЛНИТЕ ТАБЛИЦУ, ПОЖАЛУЙСТА ​

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farruxxidirovg: Я не понял помоги
madosh3991: 298. Заполните таблицу. Матем помогите пожалуйста

Ответы

Автор ответа: ksyuwi
62

№298

( 1 )

\displaystyle\\a = 10\frac{7}{10} ; b=3\frac{1}{5}\\\\\\a+b=10\frac{7}{10}+3\frac{1}{5}=\frac{107}{10}+\frac{16}{5}=\frac{107}{10}+\frac{32}{10}=\frac{139}{10}=13\frac{9}{10}\\\\\\a-b=10\frac{7}{10}-3\frac{1}{5}=\frac{107}{10}-\frac{16}{5}=\frac{107}{10}-\frac{32}{10}=\frac{75}{10}=7\frac{5}{10}=7\frac{1}{2}

( 2 )

\displaystyle\\a=9\frac{3}{7};a+b=14\frac{2}{21}\\\\\\b=14\frac{2}{21}-9\frac{3}{7}=\frac{296}{21}-\frac{66}{7}=\frac{296}{21}-\frac{198}{21}=\frac{98}{21}=4\frac{14}{21}=4\frac{2}{3} \\\\\\a-b=9\frac{3}{7}-4\frac{2}{3}=\frac{66}{7}-\frac{14}{3}=\frac{198}{21}-\frac{98}{21}=\frac{100}{21}=4\frac{16}{21}

( 3 )

\displaystyle  \\a=15\frac{9}{10};a-b=2\frac{3}{100}\\\\\\b=15\frac{9}{10}-2\frac{3}{100}=\frac{159}{10}-\frac{203}{100}=\frac{1590}{100}-\frac{203}{100}=\frac{1387}{100}= 13\frac{87}{100}\\\\\\a+b=15\frac{9}{10}+13\frac{87}{100} =\frac{159}{10}+  \frac{1387}{100}=\frac{1590}{100}+\frac{1387}{100}=\frac{2977}{100}=29\frac{77}{100}

( 4 )

\displaystyle\\b=4\frac{3}{5};a+b=23 \\\\\\a=23-4\frac{3}{5}=22\frac{5}{5}-4\frac{3}{5}=18\frac{2}{5}\\\\\\a-b=18\frac{2}{5}-4\frac{3}{5}=17\frac{7}{5}-4\frac{3}{5}=13\frac{4}{5}

( 5 )

\displaystyle\\a=5\frac{7}{20} ;b=3\frac{3}{10}\\\\\\a+b=5\frac{7}{20}+3\frac{3}{10}=\frac{107}{20}+\frac{33}{10}=\frac{107}{20}+\frac{66}{20}= \frac{173}{20}=8\frac{13}{20}\\\\\\a-b=5\frac{7}{20}-3\frac{3}{10}=\frac{107}{20}-\frac{33}{10}=\frac{107}{20}-\frac{66}{20}=\frac{41}{20}=2\frac{1}{20}

( 6 )

\displaystyle\\b=1\frac{5}{8};a-b=6\frac{3}{4}\\\\\\a=6\frac{3}{4}+1\frac{5}{8}=\frac{27}{4}+\frac{13}{8}=\frac{54}{8}+\frac{13}{8}=\frac{67}{8}=8\frac{3}{8}\\\\\\a+b=8\frac{3}{8}+1\frac{5}{8}=\frac{67}{8}+\frac{13}{8}=\frac{80}{8}=10

( 7 )

\displaystyle\\a=4\frac{3}{10};a+b=7\frac{3}{5}\\\\\\b=7\frac{3}{5}-4\frac{3}{10}=\frac{38}{5}-\frac{43}{10}=\frac{76}{10}-\frac{43}{10}=\frac{33}{10}=3\frac{3}{10}\\\\\\a-b=4\frac{3}{10}-3\frac{3}{10}=1

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