Question

надо срочно пожалуйста

Answer 1

Ответ:

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1) y = (x^2 - x - 1)^8

y' = 8(x^2 - x - 1)^7 * (2x - 1)

y' = (16x - 8)(x^2 - x - 1)^7

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2) y = $\sqrt{x^2 - x - 1}$

y' = $\frac{2x-1}{2\sqrt{x^2-x-1} }$

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3) y = (cos (4x - $\frac{\pi }{3}$)

y' = -sin(4x - $\frac{\pi }{3}$)4

y' = -2sin(4x) + 2$\sqrt{3}$ * cos(4x)

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4) y = (x^2 - 3x + 1)^7

y' = (14x - 21)(x^2 - 3x + 1)^6

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5) y = $\sqrt{x^2 - 3x + 1}$

y' = $\frac{2x - 3}{2\sqrt{x^2 - 3x + 1} }$

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6) y = cos(2x - $\frac{\pi }{4}$)

y' = - $\sqrt{2}$ * sin(2x) + $\sqrt{2}$ * cos(2x)

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7) y = (x^2 + 4x - 1)^6

y' = (12x + 24)(x^2 + 4x - 1)^5

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8) y = $\sqrt{x^2 + 4x - 1}$

y' = $\frac{x + 2}{\sqrt{x^2 + 4x - 1} }$

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