Question

быстрее пожалуйста!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Ответ:

$\frac{ {a}^{2} b}{12c} \times \frac{4c}{a {b}^{2} } = \frac{a}{3b}$

$( - \frac{2 {a}^{2} }{ {c}^{3} } )^{3} = - \frac{8 {a}^{6} }{ {c}^{9} }$

$\frac{ {a}^{3} }{ {c}^{8} } \times \frac{ {c}^{4} }{ {a}^{3} } = \frac{1}{ {c}^{4} }$

${( \frac{ {c}^{2} }{b} )}^{3} \times {( \frac{ {b}^{2} }{ {c}^{4} }) }^{2} = \frac{ {c}^{6} }{ {b}^{3} } \times \frac{ {b}^{4} }{ {c}^{8} } = \frac{b}{ {c}^{2} }$

$14 {m}^{9} \times \frac{ {n}^{2} }{7 {m}^{3} } = 2 {m}^{6} {n}^{2}$

$\frac{3a + b}{4c} \times \frac{c}{3a + b} = \frac{1}{4}$

$\frac{3c - 9}{9 {c}^{2} + 6c + 1} \times \frac{3c + 1}{c - 3} = \frac{3(c - 3)}{ {(3c + 1)}^{2} } \times \frac{3c + 1}{c - 3} = \frac{3}{3c + 1}$

$\frac{ {c}^{2} + 4c + 4 }{2c - 6} \times \frac{ {c}^{2} - 9 }{5c + 10} = \frac{ {(c + 2)}^{2} }{2(c - 3)} \times \frac{(c - 3)(c + 3)}{5(c + 2)} = \frac{(c + 2)(c + 3)}{10}$