Question

Выполните действие c²-10c+25/ c²+3c+9:6c²-30c/c³-27

Answer 1

Решение:

$\dfrac{c^2 - 10c + 25}{c^2 + 3c + 9} : \dfrac{6c^2 - 30c}{c^3 -27} = \dfrac{(c - 5)^2}{c^2 + 3c + 9} : \dfrac{6c(c - 5)}{(c-3)(c^2 + 3c + 9)} =\\ \\= \dfrac{(c - 5)^2 \cdot (c-3)(c^2 + 3c + 9)}{(c^2 + 3c + 9) \cdot 6c(c - 5)} = \dfrac{(c-5)(c-3)}{6c}$