Question

Прошу, решите пожалуйста оба варианта, очень нужно, срочно!!! ​

Answer 1

1вариант

$\frac{m {n}^{3} }{24p} \times ( - \frac{6p}{ {m}^{2}n } ) = - \frac{ {n}^{2} }{4m}$

$\frac{x - 3}{4x + 12} \div \frac{2x - 6}{ {x}^{2} + 3x} = \frac{x - 3}{4(x + 3)} \times \frac{x(x + 3)}{2(x - 3)} = \frac{x}{8}$

$\frac{72 {a}^{5} {b}^{4} }{25 {y}^{8} } \times \frac{1}{24 {a}^{7} {b}^{9} } = \frac{3}{25 {y}^{8} {a}^{2} {b}^{5} }$

$\frac{(x - 5)(x + 5)}{x(x - 6)} \times \frac{(x - 6)(x + 6)}{x(x + 5)} = \frac{(x - 5)(x - 6)}{ {x}^{2} }$

$\frac{3a}{a - 4} - \frac{a + 2}{5(a - 4)} \times \frac{240}{a(a + 2)} = \frac{3a}{a - 4} - \frac{48}{a(a - 4)} = \frac{3 {a}^{2} - 48}{a(a - 4)} = \frac{3(a - 4)(a + 4)}{a(a - 4)} = \frac{3(a + 4)}{a}$

$\frac{a + 4}{ {(a - 3)}^{2} } \times \frac{2(a - 3)}{(a - 4)(a + 4)} - \frac{2}{a - 4} = \frac{2}{3 - a} \\ \frac{2}{(a - 3)(a - 4)} - \frac{2}{a - 4} = \frac{2}{3 - a} \\ \frac{2 - 2(a - 3)}{(a - 3)(a - 4)} = \frac{2}{3 - a} \\ \frac{2 - 2a + 6}{(a - 3)(a - 4)} = \frac{2}{3 - a} \\ \frac{2(4 - a)}{(a - 3)(a - 4)} = \frac{2}{3 - a} \\ \frac{2}{3 - a} = \frac{2}{3 - a}$