Question

упростите выражения :

(√6-√2)³+√48

Answer 1

$( sqrt{6}- sqrt{2})^3+ sqrt{48}= sqrt{2} ^3( sqrt{3}-1)^3+ sqrt{2^4*3}=$
$sqrt{2} ^3( sqrt{3}^3-3 sqrt{3}^2+3 sqrt{3} -1)+ 4sqrt{3}=$
$2sqrt{2}(3 sqrt{3}-3 *3+3 sqrt{3} -1)+ 4sqrt{3}=$
$2sqrt{2}(6sqrt{3}-10)+ 4sqrt{3}=12 sqrt{6}-20 sqrt{2}+4 sqrt{3}$