Question

X-у=2
x² - y² = 8, решитесистему методом подстановки​

Answer 1

Объяснение:

$\left \{ {{x-y=2} \atop {x^2-y^2=8}} \right. \ \ \ \ \left \{ {{y=x-2} \atop {x^2-(x-2)^2=8}} \right. \ \ \ \ \left \{ {{y=x-2} \atop {x^2-(x^2-4x+4)=8}} \right.\ \ \ \ \left \{ {{y=x-2} \atop {x^2-x^2+4x-4=8}} \right.\\\left \{ {{y=x-2} \atop {4x=12\ |:4}} \right. \ \ \ \ \left \{ {{y=1} \atop {x=3}} \right. .$

Ответ: (3;1).