Question

Помогите с алгеброй пожалуйста)))​

Answer 1

1) y = 5x²       y = 45x

5x² = 45x

5x² - 45x = 0

5x(x - 9) = 0

x₁ = 0      y₁ = 45 * 0 = 0

x - 9 = 0

x₂ = 9     y₂ = 45 * 9 = 405

Ответ : (0 , 0)  ;  (9 ; 405)

$2)y=-\frac{1}{3}x^{2}\\y=x-6\\\\-\frac{1}{3}x^{2} =x-6\\\\-\frac{1}{3}x^{2}-x+6=0|*(-3)\\\\x^{2} +3x-18=0\\\\x_{1} =-6\\\\x_{2} =3\\\\y_{1} =-6-6=-12\\\\y_{2}=3-6=-3\\\\Otvet:\boxed{(-6;-12),(3;-3)}$