Question

(a1+)(a-2)(a-3)
(3a-2)(a+3)(a-7)

Answer 1

Ответ:

1) $(a+1)*(a-2)*(a-3)=(a^2-2a+a-2)*(a-3)=(a^2-a-2)*(a-3)=a^3-3a^2-a^2+3a-2a+6=a^3-4a^2+a+6$

2) $(3a-2)*(a+3)*(a-7)=(3a^2+9a-2a-6)*(a-7)=(3a^2+7a-6)*(a-7)=3a^2-21a^2+7a^2-49a-6a+42=3a^3-14a^2-55a+42$