Question

Сократить дробь y²-8y+12/12y-y²-20

Answer 1

Ответ:

Объяснение:

y²-8y+12/12y-y²-20 = y²-2y-6y+12/-y²+12y-20 = y(y-2)-6(y-2)/-y²+10y+2y-20 = (y-2)(y-6)/-y(y-10)+2(y-10) = (y-2)(y-6)/(y-10)(y-2) = - (y-6)/(y-10) = 6-y/y-10