Question

даю 70 балов за решение задачи ​

Answer 1

$1)\left \{ {{5x+15>0} \atop {2x-5<0}} \right.\\\\\left \{ {{5x>-15} \atop {2x<5}} \right. \\\\\left \{ {{x>-3} \atop {x<2,5}} \right.\\\\Otvet:\boxed{x\in(-3;2,5)}\\\\\\2)\left \{ {{2x+3>x-1} \atop {x+s<0=2}} \right. \\\\\left \{ {{2x-x>-1-3} \atop {x<-5}} \right.\\\\\left \{ {{x>-4} \atop {x<-5}} \right. \\\\Otvet:\boxed{x\in \oslash}$