Предмет: Геометрия, автор: dimasik15051984

В параллелограмме ABCD угол D равен 135°, диагональ AC образует со стороной BC угол 10°.
Какой угол образует эта диагональ со стороной CD?
СРОЧНО!!!!! ПОЖАЛУЙСТА, С ПОДРОБНЫМ ОБЪЯСНЕНИЕМ !!!!!

Ответы

Автор ответа: vpolitovska2002

1) 180-135=45(за власт суми одностор кутів)
2)45-10=35 , кут АСD=35

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