Question

Решить неравенство дам 50 баллов

Answer 1

$\left \{ {{\frac{-8-2x}{5+(6-x)^{2}}\leq0} \atop {1+5x\geq6(2x-1) }} \right.\\\\\left \{ {{\frac{-8-2x}{5+36-12x+x^{2}}\leq0} \atop {1+5x\geq12x-6 }} \right.\\\\\left \{ {{\frac{-2(x+4)}{x^{2}-12x+41}\leq0} \atop {5x-12x\geq-6-1 }} \right.\\\\\left \{ {{\frac{x+4}{x^{2}-12x+41}\geq0 } \atop {-7x\geq-7 }} \right.\\\\\left \{ {{x^{2}-12x+41>0prix\in R \Rightarrow x+4\geq0 } \atop {x\leq1 }} \right. \\\\\left \{ {{x\geq-4 } \atop {x\leq1 }} \right.\\\\Otvet:\boxed{x\in [-4;1]}$