Question

sin(30):sin(15) СРОЧНО​

Answer 1

Ответ:

$sin30^\cdot :sin15^\circ =\dfrac{2\, sin15^\circ \cdot cos15^\circ }{sin15^\circ }=2\, cos15^\circ =2\cdot \dfrac{\sqrt3+1}{2\sqrt2}=\dfrac{\sqrt3+1}{\sqrt2}=\\\\\\=\dfrac{\sqrt2\cdot (\sqrt3+1)}{2}$