Question

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Answer 1

$3: 4^{2} -5: \frac{2}{3} +(1\frac{1}{2})^{2} = \frac{3}{4^{2}} -5 * \frac{3}{2} + (\frac{3}{2})^{2} =\frac{3}{16} -\frac{15}{2} + \frac{9}{4} =-\frac{117}{16} +\frac{9}{4} = \frac{-117+36}{16} = -\frac{81}{16} =5\frac{1}{16}$

$(1\frac{1}{2} + \frac{6}{7}): (\frac{3}{5}-\frac{2}{7})-(1\frac{1}{2})^{3} =(\frac{3}{2} +\frac{6}{7} ): \frac{11}{35} - (\frac{3}{2} )^{3} = \frac{33}{14}*\frac{35}{11} -\frac{27}{8} = \frac{3}{2} *5-\frac{27}{8} = \frac{15}{2} -\frac{27}{8} = \frac{33}{8} = 4\frac{1}{8}$

$(-\frac{1}{2} )^{3} -3:2^{2} * (\frac{3}{4}-\frac{7}{15}:\frac{2}{5})=-\frac{1}{8}-3:2^{2}*(\frac{3}{4}-\frac{7}{15}*\frac{5}{2}) = -\frac{1}{8} -3:2^{2} *(\frac{3}{4}-\frac{7}{3}*\frac{1}{2} )= -\frac{1}{8} -3:2^{2} *(\frac{3}{4}-\frac{7}{6})=-\frac{1}{8} -3:2^{2} *(-\frac{5}{12} )=-\frac{1}{8}+\frac{3}{2^{2}} * \frac{5}{12} =-\frac{1}{8} +\frac{1}{4}*\frac{5}{4} =-\frac{1}{8} +\frac{5}{16}=\frac{3}{16}}$

$(\frac{2}{7} -\frac{1}{3})* (3\frac{1}{2} )^{2} +(-\frac{2}{5})^{2}: \frac{9}{50}=-\frac{1}{21} *3\frac{1}{2}^{2} + (\frac{2}{5})^{2}* \frac{50}{9}= -\frac{3\frac{1}{2}^{2} }{21} + \frac{4}{25} * \frac{50}{9} = -\frac{(\frac{7}{2}^{2})}{21} +4*\frac{2}{9} = -\frac{\frac{49}{4} }{21} +\frac{8}{9} = -\frac{7}{12} +\frac{8}{9}=\frac{11}{36}$