Question

найдите разность 1)7 5/6-3 2/3 2)8 5/12-6 7/20 3)11 11/12-5 7/9 4)9 17/24-8 11/36​

Answer 1

Відповідь:

1)7 5/6-3 2/3

$7\frac{5}{6} -3\frac{2}{3} =\frac{47-22}{6} =\frac{25}{6} =4\frac{1}{6}$

2)8 5/12-6 7/20

$8\frac{5}{12}-6\frac{7}{20} =\frac{101}{12}-\frac{127}{12} =\frac{101*5-127*3}{60} =\frac{505-381}{60} =\frac{124}{60} =2\frac{4}{60} =2\frac{1}{15}$

3)11 11/12-5 7/9

$11\frac{11}{12} -5\frac{7}{9} =\frac{143}{12} -\frac{52}{9} =\frac{143*3-52*4}{36} =\frac{429-208}{36}=\frac{221}{36} =6\frac{5}{36}$

4)9 17/24-8 11/36​

$9\frac{17}{24}-8\frac{11}{36} =\frac{233}{24} -\frac{299}{36} =\frac{233*3-299*2}{72} =\frac{699-598}{72} =\frac{101}{72} =1\frac{29}{72}$