Предмет: Физика, автор: Ford1234577889

Определите частоту вращения колес поезда, имеющих диаметр 0,8 м, при скорости поезда 54 км/ч.

Аноним: V=W*R=2П*частоту *R
Аноним: отсюда по пропорции находим частоту

Ответы

Автор ответа: Vasily1975
1

Ответ: ≈6 Гц.

Объяснение:

За 1 оборот колесо пройдёт путь L1=π*D, где D=0,8 м - диметр колеса. А поезд за 1 с проходит путь L2=54/3,6=15 м. Поэтому за 1 с колесо совершит n=L2/L1=15/(0,8*π)≈6 оборотов. Отсюда период обращения колеса T≈1/6 с, а частота f=1/T≈6 Гц.

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