Question

Вопрос на 1 минуту!!!
чему равно выражение:
tg(arcsin(0,6))?

Answer 1

arcsin(0,6) = A
sinA = 0,6
cos^2(A) = 1 - sin^2(A) = 1 - 9/25 = 16/25
cosA = 4/5
1+tg^2(A) = 1/cos^2(A)
tg^2(A) = 1/cos^2(A) - 1 = 25/16 - 1 = 9/16
tgA = tg(arcsin(0,6)) = 3/4