Question

(а²-а²+6)-(4а³+8а²-11)пж срочно​

Answer 1

Ответ:

(а²-а²+6)-(4а³+8а²-11)=(а-6)-(12$a^{5}$-11)

Answer 2

(а2-а2+6)-(4а3+8а2-11)=5а3

((-а4)+6)-(4а3+8а2-11)

4+8-11=1

6-1=5

-а4+а3+а2=а3