Question

найти область определения функции ​
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Answer 1

Ответ:

$\left\{\begin{array}{l}x^2+7x-9\geq 0\\36-x^2\ne 0\end{array}\right\ \ \left\{\begin{array}{l}\Big(x-\dfrac{-7-\sqrt{85}}{2}\Big)\Big(x-\dfrac{-7+\sqrt{85}}{2}\Big)\geq 0\\\\(6-x)(6+x)\ne 0\end{array}\right\\\\\\\left\{\begin{array}{l}x\in \Big(-\infty \, ;\,\dfrac{-7-\sqrt{85}}{2}\ \Big]\cup \Big[\ \dfrac{-7+\sqrt{85}}{2}\ ;+\infty \, \Big)\\\\x\ne -6\ ,\ x\ne 6\end{array}\right$

$x\in \Big(-\infty \, ;\ \dfrac{-7-\sqrt{85}}{2}\Big]\cup \Big[\ \dfrac{-7+\sqrt{85}}{2}\ ;\ 6\ \Big)\cup \Big(\ 6\, ;\, +\infty \Big)$