Question

(a+6b/a²-6ab -1/a):b/6b-a

Answer 1

Ответ:

$(\frac{a+6b}{a^2-6ab} -\frac{1}{a} ):\frac{b}{6b-a}= (\frac{a+6b}{a*(a-6b)} -\frac{1}{a} )*\frac{6b-a}{b} = \frac{a+6b-(a-6b)}{a*(a-6b)} * \frac{-(a-6b)}{b} = \frac{a+6b-a+6b}{a} * \frac{-1}{b} = \frac{12b}{a} * \frac{-1}{b} = \frac{12}{a} * (-1)=-\frac{12}{a}$

Объяснение: