Question

pozalusta pomogitji
nji kak njipoluchaitsa

Answer 1

Ответ:

x=64

Пошаговое объяснение:

$log_{a}b=\frac{log_{c}b}{log_{c}a}$

$log_{\sqrt{2} }x-log_{4}x+log_{\frac{1}{2} }x-log_{8}x=1\\\\\frac{log_{2}x}{log_{2}\sqrt{2} } -\frac{log_{2}x}{log_{2}4} +\frac{log_{2}x}{log_{2}\frac{1}{2} } -\frac{log_{2}x}{log_{2}8} =1\\\\2 log_{2}x-\frac{1}{2} log_{2}x+(-log_{2}x)-\frac{1}{3} log_{2}x=1\\\\\frac{1}{2} log_{2}x-\frac{1}{3} log_{2}x=1\\\\\frac{1}{6} log_{2}x=1\\\\log_{2}x=6\\\\x=2^{6}\\x=64$