Question

ДАМ 35 БАЛЛОВ!!!
304. Решить систему линейных уравнений
$\left \{ {{\frac{2x-1}{7}\leq \frac{x-2}{3}} \atop {x^{2}-23x\ \textgreater \ 0}} \right.$

Answer 1

Ответ:

$\left\{\begin{array}{l}\dfrac{2x-1}{7}\leq \dfrac{x-2}{3}\\x^2-23x>0\end{array}\right\ \ \left\{\begin{array}{l}3(2x-1)\leq 7(x-2)\\x\, (x-23)>0\end{array}\right\ \ \left\{\begin{array}{l}6x-3\leq 7x-14\\x(x-23)>0\end{array}\right\\\\\\\left\{\begin{array}{l}x\geq 11\\x\in (-\infty ;0)\cup (23\, ;\, +\infty \, )\end{array}\right\ \ \ \Rightarrow \ \ \ x\in (\, 23\, ;+\infty \, )$