Question

Алгебра! Помогите!!!!!!!!!!!!!!​

Answer 1

$\frac{x^{2}+25y^{2}}{x-5y} +\frac{10xy}{5y-x} =\frac{x^{2}+25y^{2}}{x-5y}-\frac{10xy}{x-5y}=\frac{x^{2}-10xy+25y^{2}}{x-5y} =\frac{(x-5y)^{2}}{x-5y} =x-5y=\\\\=2017-5*\frac{1}{5} =2017-1=2016$