Question

плиз помогите по геометрии​

Answer 1

Ответ:

sinC= 5/13

cosC = 12/13

tgC = 5/12

ctgC =  $2\frac{2}{5}$

Объяснение:

ВС = $\sqrt{12^{2}+5^{2} } = \sqrt{144+25} =\sqrt{169} =13$

sinC= BA / BC = 5/13

cosC= CA / BC = 12/13

tgC= BA / AC = 5/12

ctgC= AC/BA = 12/5= $2\frac{2}{5}$