Question

Помогите 4 или 5 пожалуйста ❤️

Answer 1

Ответ:

4)

$у' = - 8 \times \frac{(( {x + 1)}^{3})'}{(( {x + 1)}^{3}) ^{2}} = \\ = - 8 \times \frac{3( {x + 1)}^{2} }{( {x + 1)}^{6} } = - \frac{ 8 \times 3}{( {x + 1)}^{4} } = \\ = - \frac{24}{( {x + 1)}^{4} }$

x0=-2

$у(x0) = - \frac{24}{( { - 2 + 1)}^{4} } = - 24$

5)

$у'= \frac{1}{12} \times 12 \: cos \: \frac{x}{12} = \cos \frac{x}{12}$

x0=-2

$у(x0)=cos ( - \frac{ 2}{12} ) = \cos( - \frac{1}{6} ) = \cos \frac{1}{6}$