Question

a-2в/x+c * 3x+3c/5a-10в​

Answer 1

$\tt\displaystyle\frac{a-2b}{x+c} \cdot \frac{3x+3c}{5a-10b} = \frac{a-2b}{x+c}\cdot\frac{3(x+c)}{5(a-2b)} = \\\\\\=\frac{1}{1}\cdot\frac{3\cdot1}{5\cdot1} =1\cdot \frac{3}{5} = \frac{3}{5}$