Question

помогите пж по Алгебре​

Answer 1

Пошаговое объяснение:

$3) \\ ( \frac{1}{3} )^{ - 3} - ( \frac{6}{7} )^{0} + ( \frac{1}{2}) ^{2} = 27 + \frac{1}{4} = \frac{108 + 1}{4} = \frac{109}{4} = 27 \frac{1}{4}$

$(7 {x}^{2} - 5x + 3) - (5x ^{2} - 4) = 7 {x}^{2} - 5x + 3 - 5x ^{2} + 4 = 2 {x}^{2} - 5x + 7$

$5) \\ 5 {a}^{2} ( 2a - {a}^{2} ) = 10 {a}^{3} - 5 {a}^{4}$

$6) \\ 1. \\ 7ax - 7bx = 7x(a - b) \\ 2.16x {y}^{2} + 12 {x}^{2} y = 4xy(4y + 3x)$

$1)$

$( - \frac{3}{2} {b}^{4} c)^{2} \times (2bc ^{3} ) ^{3} = \frac{9}{4} {b}^{8} {c}^{2} \times 8 {b}^{3} {c}^{9} = 18 {b}^{11} {c}^{11}$