Question

Вычислите 5^-8*5^10-7^-5:7^-5 ((3/4)^2)^-1

Answer 1

Ответ:

$5 {}^{ - 8} \times 5 {}^{10} - {}^{ - 5} \div 7 {}^{ - 5} + (( \frac{3}{4}) {}^{2} ) {}^{ - 1} = 5 {}^{2} - 7 {}^{ - 5} \div 7 {}^{ - 7} + (( \frac{3}{4} ) {}^{2} ) {}^{ - 1} = 5 {}^{2} - 1 + (( \frac{3}{4} ) {}^{2} ) {}^{ - 1} = 5 {}^{2} - 1 + ( \frac{3}{4} ) {}^{ - 2} = 25 - 1 + ( \frac{ 3}{4} {}^{ - 2} = 25 - 1 + ( \frac{4}{3} ) {}^{2} = 24 + ( \frac{4}{3} ) {}^{2} = 24 + \frac{16}{9} = \frac{238}{9}$

Ответ -

$\frac{232}{9}$