Question

Решение на это под буквой б)
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Answer 1

$2 frac{4}{15}-4frac{1}{5}*(1frac{5}{6}-frac{41}{42})= 2 frac{4}{15}-4frac{1}{5}*( frac{11}{6}- frac{41}{42})=2 frac{4}{15}-4frac{1}{5}*( frac{77}{42}- frac{41}{42})=2 frac{4}{15}-frac{21}{5}* frac{6}{7}= frac{34}{15}- frac{21*6}{5*7}= frac{34}{15}- frac{18}{5}= frac{34}{15}- frac{54}{15}=- frac{20}{15}=- frac{4}{3}=- 1 frac{1}{3}$ 

Answer 2

2 4/15 - 4 1/5*(1 5/6 - 41/42)= - 1 1/3
1) 1 5/6 - 41/42= 1 35/42 - 41/42= 77/72 - 41/42= 36/42=6/7
2) 4 1/5*6/7= 21/5*6/7 (сокращаем 21 и 7 на 7)= 18/5= 3 3/5
3) 2 4/15 - 3 3/5= 2 4/15 - 3 9/15= - ( 3 9/15- 2 4/15)= - 1 5/15= - 1 1/3