Question

log1/4(4x+1)=-2
Помогите

Answer 1

$log_{ \frac{1}{4} }(4x + 1) = - 2, \: x > - \frac{1}{4} \\ 4x + 1 =( \frac{1}{4} ) {}^{ - 2} \\ 4x = {4}^{2} - 1 \\ 4x = 15 \\ x= \frac{15}{4} \\ x = 3.75$

Ответ: 3.75