Question

2x(x^2-3)^5dx Найдите

Answer 1

Ответ:

$\int 2x(x^2-3)^5\, dx=\Big[\ t=x^2-3\ ,\ dt=2x\, dx\ \Big]=\int t^5\, dt=\dfrac{t^6}{6}+C=\dfrac{(x^2-3)^6}{6}+C$