Question

Решение уравнения

4 ^(2x+3) : 4 ^(−6x+5) = 64

Answer 1

$\frac{ {4}^{2x + 3} }{ {4}^{ - 6x + 5} } = 64 \\ \frac{ {4}^{2x + 3} }{ {4}^{ - 6x + 5} } = {4}^{3} \\ \frac{ {4}^{2x + 3} }{ {4}^{ - 6x + 5 + 3} } = 0 \\ (2x + 3) - ( - 6x + 8) = 0 \\ 2x + 3 + 6x - 8 = 0 \\ 8x = 5 \\ x = \frac{5}{8} = 0.625$