Question

а)1-k=3/5+1/10
б) t + 1 =4/9+2/3
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Answer 1

Ответ:

а)

$1 - k = \frac{3}{5} + \frac{1}{10} \\ 1- k = \frac{6 + 1}{10} \\ 1 - k = \frac{7}{10} \\ k = 1 - \frac{7}{10} \\ k = \frac{3}{10}$

б)

$t + 1 = \frac{4}{9} + \frac{2}{3} \\ t + 1 = \frac{10}{9} \\ t = \frac{10}{9} - 1 \\ t = \frac{1}{9}$

Answer 2

Ответ:

а)

1-k=3/5+1/10

1-k=6/10+1/10

1-k=7/10

k=1-7/10

k=10/10-7/10

k=3/10

б)

t + 1 =4/9+2/3

t + 1 =4/9+6/9

t + 1 =10/9

t=10/9-1

t=10/9-9/9

t=1/9