Question

Решите данное уравнение

Answer 1

Ответ: x = 1

Объяснение:

$\sqrt{x^2+4x-5} = 1 - x\\\\(\sqrt{x^2+4x-5})^2 = (1-x)^2\\\\x^2+4x-5 = 1 - 2x + x^2\\\\4x - 5 = 1 - 2x\\\\4x + 2x = 1 + 5\\\\6x = 6 \\\\x = 1$