Question

Решите уравнение:
(x+4)(x-3)-(x-5)(x+2)=6.
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Answer 1

$(x+4)(x-3)-(x-5)(x+2)=6\\x^2-3x+4x-12-(x^2+2x-5x-10)=6\\x^2-3x+4x-12-x^2+3x+10=6\\4x-2=6\\4x=8\\x = 2$