Предмет: Алгебра, автор: Аноним

Дана функция f(x)=5x-4 найдите наибольший корень уравнения  f ^{2} (x)=16f(x)

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Автор ответа: Матов
0
f(x)=5x-4\ f^2(x)=f(x)*f(x)=(5x-4)^2\ 16*f(x)=16(5x-4)\ \ (5x-4)^2=16(5x-4)\ 25x^2-40x+16=80x-64\ 25x^2-120x+80=0\ 5x^2-24x+16=0\ D=16^2\ x_{1}=frac{4}{5}\ x_{2}=4

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