Question

ОЧЕНЬ СРОЧНО 3 ЗАДАНИЕ​

Answer 1

$\Big(1,6a+\dfrac{1}{12}-5a^4\Big)-\Big(0,5a-\dfrac{5}{6}-5a^4\Big)=0\\\\1,6a+\dfrac{1}{12}-5a^4-0,5a+\dfrac{5}{6}+5a^4=0\\\\\Big(1,6a-0,5a\Big)+\Big(\dfrac{1}{12}+\dfrac{5}{6}\Big)+\Big(-5a^4+5a^4\Big)=0\\\\1,1a+\dfrac{11}{12}=0\\\\1,1a=-\dfrac{11}{12}\\\\a=-\dfrac{11}{12\cdot 1,1}\ \ \ ,\ \ \ a=-\dfrac{11\cdot 10}{12\cdot 11}\ \ \ ,\ \ \ a=-\dfrac{10}{12}\ \ ,\ \ \ \boxed {\ a=-\dfrac{5}{6}\ }$