Question

Решите систему уравнений: $\left \{ {{x+y=3} \atop {x^3+x^2y=12}} \right.$

Answer 1

x + y = 3

x³ + x²y = 12

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x + y = 3

x²(x + y) = 12

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x² = 4

1. x = 2

x + y = 3

y = 1

2. x = -2

x + y = 3

y = 5

ответ (-2, 5) (2, 1)