Question

Помогите,пожалуйста 7.

Answer 1

$3arctg^{2}x-2\pi*arctgx-\pi^{2}=0\\\\arctgx=m\\\\3m^{2} -2\pi*m-\pi ^{2}=0\\\\D=(2\pi)^{2} -4*3*(-\pi ^{2})=4\pi ^{2}+12\pi ^{2}=16\pi ^{2}=(4\pi)^{2}\\\\m_{1}=\frac{2\pi -4\pi }{6}=-\frac{\pi }{3}\\\\m_{2} =\frac{2\pi+4\pi}{6}=\pi-neyd\\\\arctgx=-\frac{\pi }{3}\\\\x=-\sqrt{3}$