Question

$\frac{a + 2}{a { }^{2} - 2a + 1?} \div \frac{a {}^{2} - 4 }{3a - 3 }$
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Answer 1

✔ответ ✔

●: 1) $\frac{a+2}{a^2-2a+1} : \frac{a^2-4}{3a-3} - \frac{3}{a-2}$

$\frac{a+2}{(a-1)^2} * \frac{3a-3}{a^2-4} - \frac{3}{a-2}$

$\frac{a+2}{(a-1)^2} * \frac{3(a-1)}{(a-2)*(a+2)} - \frac{3}{a-2}$

$\frac{1}{a-1} * \frac{3}{a-2} - \frac{3}{a-2}$

$\frac{3}{(a-1)*(a-2)} - \frac{3}{a-2}$

$\frac{3-3(a-1)}{(a-1)*(a-2)}$

$\frac{3-3a+3}{(a-1)*(a-2)}$

$\frac{6-3a}{(a-1)*(a-2)}$

$\frac{-3a+6}{(a-1)*(a-2)}$

$\frac{-3(a-2)}{(a-1)*(a-2)}$

$\frac{-3}{a-1}$

$-\frac{3}{a-1}$