Question

Помогите пожалуйста как решить эту задачу
(x-²x-2) (x²-6x+5)=0 эту и
(x³-9x) (x²-6x+8)=0
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Answer 1

$(x-²x-2) (x²-6x+5)=0 \\ x {}^{2} - x - 2 = 0 \\ x {}^{2} - 6x + 5 = 0 \\ x = - 1 \\ x = 2 \\ x = 1 \\ x = 5 \\ \\ \\ x(1) = - 1 \\ x(2) = 1 \\ x(3) = 2 \\ x(4) = 5 \\ \\ \\ (x³-9x) (x²-6x+8)=0 \\ x {}^{3} - 9x = 0 \\ x {}^{2} - 6x + 8 = 0 \\ x = 0 \\ x = - 3 \\ x = 3 \\ x = 2 \\ x = 4 \\ \\ \\ \\ x(1) = - 3 \\ x(2) = 0 \\ x(3) = 2 \\ x(4) = 3 \\ x(5) = 4$