Question

помогити с заданием пожалуйста ​

Answer 1

$\frac{x - 2b}{ {x}^{2} - 2bx } = \frac{x - 2b}{x(x - 2b)} = \frac{1}{x}$

$\frac{3x + a}{ {(x + a)}^{2} } + \frac{x + 3a}{ {(x + a)}^{2} } = \frac{3x + a + x + 3a}{ {(x + a)}^{2} } = \frac{4x + 4a}{(x + a) {}^{2} } = \frac{4(x + a)}{ {(x + a)}^{2} } = \frac{4}{x + a}$

$\frac{3x}{y} - \frac{x}{y} = \frac{3x - x}{y} = \frac{2x}{y}$

$\frac{1}{ {a}^{2} } + \frac{a - 2}{a} = \frac{1 + a(a - 2)}{ {a}^{2} } = \frac{1 + {a}^{2} - 2a}{ {a}^{2} } = \frac{(a - 1) {}^{2} }{ {a}^{2} }$