Question

Срочно! Даю 20 баллов!

Answer 1

Ответ:

$y=\sqrt{x}\\\\a)\ \ M(x\, ;\, 8\sqrt3)\ \ \to \ \ \ y(x)=8\sqrt3\ \ ,\ \ \sqrt{x}=8\sqrt3\ \ ,\ \ \ x=(8\sqrt3)^2\ \ ,\\\\x=64\cdot 3=192\\\\b)\ \ x\in [\, 0\, ;\, 25\ ]\ \ \to \ \ 0\leq x\leq 25\ \ ,\ \ \sqrt{0}\leq \sqrt{x}\leq \sqrt{25}\ \ , \ \ 0\leq \sqrt{x}\leq 5\ ,\\\\0\leq y\leq 5\ \ \ \to \ \ y\in [\ 0\, ;\, 5\ ]\\\\c)\ \ y\in [\, 17\, ;\, 25\ ]\ \ \to \ \ \ 17\leq \sqrt{x}\leq 25\ \ ,\ \ 17^2\leq x\leq 25^2\ \ ,\ \ \ 289\leq x\leq 625\ ,\\\\x\in [\ 289\, ;\, 625\ ]$

$d)\ \ y\leq 7\ \ \to \ \ \ \sqrt{x}\leq 7\ \ ,\ \ 0\leq x\leq 49\ \ ,\ \ \ x\in [\ 0\, ;\, 49\ ]$