Question

дам 35 сделаите по алгебре сложную задачку

Answer 1

$\frac{t^{2}+t+1}{t^{3}-125}-\frac{4t+24}{125-t^{3}}=\frac{t^{2}+t+1}{t^{3}-125}+\frac{4t+24}{t^{3}-125}}=\frac{t^{2}+t+1+4t+24}{t^{3}-125}}}=\frac{t^{2}+5t+25}{(t-5)(t^{2}+5t+25)} =\frac{1}{t-5}\\\\t=7\\\\\frac{1}{t-5} =\frac{1}{7-5}=\frac{1}{2}\\\\Otvet:\boxed{\frac{1}{2}}$