Question

билимлэнд срочно !!
​

Answer 1

$y=\sqrt{\dfrac{x+1}{x+3}}\ \ ,\ \ \ x=\sqrt3-2\\\\\\y(\sqrt3-2)=\sqrt{\dfrac{\sqrt3-2+1}{\sqrt3-2+3}}=\sqrt{\dfrac{\sqrt3-1}{\sqrt3+1}}=\sqrt{\dfrac{(\sqrt3-1)^2}{(\sqrt3-1)(\sqrt3+1)}}=\\\\\\=\dfrac{|\sqrt3-1|}{\sqrt2}=\dfrac{\sqrt3-1}{\sqrt2}=\boxed{\dfrac{\sqrt2\, (\sqrt3-1)}{2}=\dfrac{\sqrt6-\sqrt2}{2}\, }\\\\\\\\ili\ \ ...=\sqrt{\dfrac{(\sqrt3-1)^2}{(\sqrt3-1)(\sqrt3+1)}}=\sqrt{\dfrac{4-2\sqrt3}{3-1}}=\sqrt{\dfrac{2\, (2-\sqrt3)}{2}}=\sqrt{2-\sqrt3}$