Question

Решите систему уравнений:
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Answer 1

Объяснение:

$\\\\\left \{ {{2x-\frac{x+1}{2}\leq \frac{x+1}{3} \ |*6 } \atop {(x+5)*(x-3)+41 \geq (x-6)^2}} \right. \ \ \ \ \left \{ {{12x-3*(x+1)\leq2*(x+1) } \atop {x^2+2x-15+41\geq x^2-12x+36 }} \right. \ \ \ \ \left \{ {{12x-3x-3\leq2x+2 } \atop {14x\geq 10\ |:14}} \right. \\ \left \{ {{7x\leq 5\ |:7} \atop {x\geq \frac{5}{7} }} \right.\ \ \ \ \left \{ {{x\leq \frac{5}{7} } \atop {x\geq \frac{5}{7} }} \right.\ \ \ \Rightarrow$

Ответ: x=5/7.