Question

Помогите со 2 номером 2 варианта

Answer 1

$\frac{Sin(\pi-x)Cos(\frac{3\pi }{2}+x)tg(x-\frac{3\pi }{2})}{Cos(\frac{\pi }{2}-x)Cos(\frac{3\pi }{2}-x)tg(x-\pi)}=\frac{Sinx*Sinx*(-Ctgx)}{Sinx*(-Sinx)*tgx}=\frac{Ctgx}{tgx}=\frac{Ctgx}{\frac{1}{Ctgx}}=Ctg^{2}x\\\\Otvet:\boxed{Ctg^{2}x}$