Question

добуток одночленів: 0,5 ( у⁶)³ і ( 2у⁸)⁵​

Answer 1

$0.5( {y}^{6} ) {}^{3} \times (2 {y}^{8} ) {}^{5} = 0.5 {y}^{6 \times 3} \times {2}^{5} {y}^{8 \times 5} = 0.5 \times 32 {y}^{18} {y}^{40} = 16 {y}^{18 + 40} = 16 {y}^{58}$